> #mechanics , #physics > A 1.6m long barrel propels an object of mass 70kg.If the object is propelled in barrel for 1.2s , find the average net force exerted on it?
Jul 23

# A 1.6m long barrel propels an object of mass 70kg.If the object is propelled in barrel for 1.2s , find the average net force exerted on it?

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Jul 23
To find the average net force exerted on the object, we can use the equation:

F = m * a

Where:
F = force
m = mass of the object (70kg)
a = acceleration

First, we need to find the acceleration of the object. We can use the equation:

s = ut + (1/2)at^2

Where:
s = distance traveled (1.6m)
u = initial velocity (0 m/s, as the object starts from rest)
t = time taken (1.2s)

Rearranging the equation to solve for acceleration:

1.6 = 0 + (1/2) * a * (1.2)^2
1.6 = 0 + 0.6a
a = 1.6 / 0.6
a = 2.67 m/s^2

Now, we can calculate the average net force exerted on the object:

F = 70kg * 2.67 m/s^2
F = 186.9 N

Therefore, the average net force exerted on the object is 186.9 Newtons.
0
Jul 23
Given:

- Length of barrel, L = 1.6m
- Mass of object, m = 70kg
- Time, t = 1.2s

To find:

- Average net force exerted on the object, F

Solution:

The acceleration of the object can be calculated using the equation:

```
a = (v - u) / t
```

where:

- a is the acceleration
- v is the final velocity
- u is the initial velocity
- t is the time

Since the object starts from rest, u = 0. The final velocity can be calculated by using the equation:

```
v = L / t
```

Substituting the given values, we get:

```
v = 1.6m / 1.2s = 1.33m/s
```

Therefore, the acceleration of the object is:

```
a = (1.33m/s - 0) / 1.2s = 1.11m/s²
```

The net force exerted on the object is given by:

```
F = ma
```

Substituting the values of m and a, we get:

```
F = (70kg) - (1.11m/s²) = 77.7N
```

Therefore, the average net force exerted on the object is 77.7N.
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