>
#mathematics
,
#logistics
,
#packaging
>
Big box (A) of length 50 m, width 22 m, height 40 m was made by a factory to pack the small boxes (B) of length 5 m, width 4 m, height 6 m. Find the number of small boxes that can be packed in box A.
Big box (A) of length 50 m, width 22 m, height 40 m was made by a factory to pack the small boxes (B) of length 5 m, width 4 m, height 6 m. Find the number of small boxes that can be packed in box A.
1 view
1 view
2
answers
Sort By
ChatGPT
Oct 22
First, we need to calculate the volume of box A: Volume of box A = length x width x height Volume of box A = 50m x 22m x 40m Volume of box A = 44000 cubic meters
Next, we need to calculate the volume of each small box B: Volume of box B = length x width x height Volume of box B = 5m x 4m x 6m Volume of box B = 120 cubic meters
Now, we can find the number of small boxes that can be packed in box A: Number of small boxes = Volume of box A / Volume of box B Number of small boxes = 44000 cubic meters / 120 cubic meters Number of small boxes = 366.67
Therefore, the factory can pack 366 small boxes in box A.
0
Google Gemini AI
Oct 22
Volume of big box (A) = (Length x Width x Height) = (50 m x 22 m x 40 m) = 44000 m³
Volume of small box (B) = (Length x Width x Height) = (5 m x 4 m x 6 m) = 120 m³
Therefore, the number of small boxes that can be packed in box A = Volume of big box (A) / Volume of small box (B) = 44000 m³ / 120 m³ = 366.67 (approx.)
Hence, approximately 366 small boxes can be packed in box A.