more than 4 weeks ago

1 view

1 view

Sort By

ChatGPT

more than 4 weeks ago

To calculate the pressure exerted by the water on the driver, we can use the formula for pressure:

Pressure = density x gravity x depth

Given:

Density of seawater = 1025 kg/m^3

Gravity = 9.81 m/s^2

Depth = 20 cm = 0.2 m

Plugging in the values:

Pressure = 1025 kg/m^3 x 9.81 m/s^2 x 0.2 m

Pressure = 2007.9 Pa

Therefore, the pressure exerted by the water on the driver when driving to a depth of 20 cm below the surface of seawater is 2007.9 Pa.

Pressure = density x gravity x depth

Given:

Density of seawater = 1025 kg/m^3

Gravity = 9.81 m/s^2

Depth = 20 cm = 0.2 m

Plugging in the values:

Pressure = 1025 kg/m^3 x 9.81 m/s^2 x 0.2 m

Pressure = 2007.9 Pa

Therefore, the pressure exerted by the water on the driver when driving to a depth of 20 cm below the surface of seawater is 2007.9 Pa.

Google Gemini AI

more than 4 weeks ago

The pressure exerted by a fluid is given by the formula:

$$P = \rho g h$$

where:

- $$P$$ is the pressure in Pascals (Pa)

- $$\rho$$ is the density of the fluid in kilograms per cubic meter (kg/m³)

- $$g$$ is the acceleration due to gravity in meters per second squared (m/s²)

- $$h$$ is the depth of the fluid in meters (m)

In this case, we are given the following information:

- $$\rho = 1025 \text{ kg/m}^3$$ (density of seawater)

- $$g = 9.81 \text{ m/s}^2$$

- $$h = 0.2 \text{ m}$$

Substituting these values into the formula, we get:

$$P = (1025 \text{ kg/m}^3)(9.81 \text{ m/s}^2)(0.2 \text{ m}) = 1966.95 \text{ Pa}$$

Therefore, the pressure exerted by the water on the driver is 1966.95 Pa.

$$P = \rho g h$$

where:

- $$P$$ is the pressure in Pascals (Pa)

- $$\rho$$ is the density of the fluid in kilograms per cubic meter (kg/m³)

- $$g$$ is the acceleration due to gravity in meters per second squared (m/s²)

- $$h$$ is the depth of the fluid in meters (m)

In this case, we are given the following information:

- $$\rho = 1025 \text{ kg/m}^3$$ (density of seawater)

- $$g = 9.81 \text{ m/s}^2$$

- $$h = 0.2 \text{ m}$$

Substituting these values into the formula, we get:

$$P = (1025 \text{ kg/m}^3)(9.81 \text{ m/s}^2)(0.2 \text{ m}) = 1966.95 \text{ Pa}$$

Therefore, the pressure exerted by the water on the driver is 1966.95 Pa.