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Apr 21

# Determine the Speed At Which the Basketball at A Must Be Thrown At The Angle Of 30 degree so that it make it to the basket B?

Determine the Speed At Which the Basketball at A Must Be Thrown At The Angle Of 30 degree so that it make it to the basket B?
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Anonymous
Apr 22

To determine the speed at which the basketball at point A must be thrown at an angle of 30 degrees so that it makes it to the basket B, we need to use the following equation of motion:

h = (v2 sin2 θ) / (2g)

where h is the height of the basket, v is the initial velocity of the basketball, θ is the angle at which the basketball is thrown, and g is the acceleration due to gravity (9.81 m/s2).

Assuming the height of the basket is 3.05 meters, we can plug in the values and solve for v:

3.05 = (v2 sin2 30) / (2 * 9.81)

Simplifying the equation, we get:

v2 = (2 * 9.81 * 3.05) / sin2 30

v2 = 117.53

v = √117.53

v ≈ 10.84 m/s

Therefore, the basketball at point A must be thrown at a speed of approximately 10.84 m/s at an angle of 30 degrees to make it to the basket B.

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