> #mathematics , #problem-solving > I have 25 coins. Some are 10 cents and some are 5 cent pieces. How many of each kind do I have if their value is \$1.75?
###### Anonymous
more than 4 weeks ago

# I have 25 coins. Some are 10 cents and some are 5 cent pieces. How many of each kind do I have if their value is \$1.75?

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more than 4 weeks ago
Let x be the number of 10 cent coins and y be the number of 5 cent coins.

We can create a system of equations based on the given information:

1) x + y = 25 (total number of coins)
2) 10x + 5y = 175 (total value of coins in cents)

From equation 1, we can solve for x in terms of y:
x = 25 - y

Substitute x = 25 - y into equation 2:
10(25 - y) + 5y = 175
250 - 10y + 5y = 175
250 - 5y = 175
-5y = -75
y = 15

Now, substitute y = 15 back into x = 25 - y:
x = 25 - 15
x = 10

Therefore, you have 10 10 cent coins and 15 5 cent coins.
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more than 4 weeks ago
Let x be the number of 10-cent coins and y be the number of 5-cent coins.

We know that:

- x + y = 25 (total number of coins)
- 0.10x + 0.05y = 1.75 (total value of the coins)

Solving the first equation for x, we get:

- x = 25 - y

Substituting this into the second equation, we get:

- 0.10(25 - y) + 0.05y = 1.75
- 2.50 - 0.10y + 0.05y = 1.75
- -0.05y = -0.75
- y = 15

Therefore, there are 15 5-cent coins and 10 10-cent coins.
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