> #mathematics , #chemistry > Sodium and water are mixed, and 0.945 moles of hydrogen is recovered. How many grams of sodium hydroxide will be recovered?
Anonymous
more than 4 weeks ago

Sodium and water are mixed, and 0.945 moles of hydrogen is recovered. How many grams of sodium hydroxide will be recovered?

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ChatGPT
more than 4 weeks ago
The balanced chemical equation for the reaction between sodium and water is:

2Na + 2H2O -> 2NaOH + H2

From the equation, we can see that 2 moles of sodium react with 2 moles of water to produce 2 moles of sodium hydroxide and 1 mole of hydrogen.

Given that 0.945 moles of hydrogen is recovered, we can calculate the moles of sodium hydroxide produced:

0.945 moles H2 x (2 moles NaOH / 1 mole H2) = 1.89 moles NaOH

Now, we can calculate the mass of sodium hydroxide produced:

1.89 moles NaOH x (40.00 g NaOH / 1 mole NaOH) = 75.6 g NaOH

Therefore, 75.6 grams of sodium hydroxide will be recovered.
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Google Gemini AI
more than 4 weeks ago
Step 1: Write the balanced chemical equation.

```
2 Na + 2 H2O → 2 NaOH + H2
```

Step 2: Determine the mole ratio between hydrogen and sodium hydroxide.

From the balanced equation, we can see that 2 moles of hydrogen are produced for every 2 moles of sodium hydroxide. Therefore, the mole ratio of H2 to NaOH is 1:1.

Step 3: Calculate the moles of sodium hydroxide produced.

Since we have 0.945 moles of hydrogen, we will also have 0.945 moles of sodium hydroxide.

Step 4: Convert moles of sodium hydroxide to grams.

The molar mass of sodium hydroxide (NaOH) is 40.00 g/mol. Therefore, the mass of sodium hydroxide produced is:

```
mass of NaOH = moles of NaOH × molar mass of NaOH
```

```
mass of NaOH = 0.945 mol × 40.00 g/mol
```

```
mass of NaOH = 37.80 g
```

Therefore, 37.80 grams of sodium hydroxide will be recovered.
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