Aug 5

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ChatGPT

Aug 5

1. A car is traveling along a straight road at a constant speed of 60 km/h. Describe the linear motion of the car in terms of velocity and acceleration.

Answer: The car is moving in a straight line with a constant velocity of 60 km/h. Since the velocity is constant, the acceleration of the car is zero.

2. A ball is thrown vertically upwards with an initial velocity of 20 m/s. Describe the linear motion of the ball as it moves upwards and then falls back down to the ground.

Answer: As the ball moves upwards, its velocity decreases due to the acceleration of gravity acting in the opposite direction. At the highest point, the velocity of the ball is zero. As the ball falls back down, its velocity increases in the opposite direction until it reaches the ground.

Answer: The car is moving in a straight line with a constant velocity of 60 km/h. Since the velocity is constant, the acceleration of the car is zero.

2. A ball is thrown vertically upwards with an initial velocity of 20 m/s. Describe the linear motion of the ball as it moves upwards and then falls back down to the ground.

Answer: As the ball moves upwards, its velocity decreases due to the acceleration of gravity acting in the opposite direction. At the highest point, the velocity of the ball is zero. As the ball falls back down, its velocity increases in the opposite direction until it reaches the ground.

Google Gemini AI

Aug 5

A car travels from Kampala to Entebbe, a distance of 40 km, in 1 hour.

- (a) What is the car's average speed?

- (b) If the car maintains the same average speed, how long will it take to travel from Entebbe to Fort Portal, a distance of 250 km?

- (a) Average speed = Distance / Time = 40 km / 1 h = 40 km/h

- (b) Time = Distance / Speed = 250 km / 40 km/h = 6.25 hours

A ball is thrown vertically upwards with an initial velocity of 20 m/s.

- (a) What is the maximum height reached by the ball?

- (b) How long does it take for the ball to return to the ground?

- (a) Maximum height = (v^2) / (2g) = (20 m/s)^2 / (2 - 9.8 m/s^2) = 20.4 meters

- (b) Time to return to ground = 2 - (20 m/s) / (9.8 m/s^2) = 4.1 seconds