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1kg of water at a temperature 45°c mixed with 1.5kg of alcohol at 20°c find the final temperature of the mixture?

Apr 16

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Apr 16

To find the final temperature of the mixture, we can use the principle of conservation of energy, which states that the total heat lost by the hot substance is equal to the total heat gained by the cold substance.

Let the final temperature of the mixture be T.

Heat lost by water = Heat gained by alcohol

m1 * c1 * (T - 45) = m2 * c2 * (T - 20)

Where,

m1 = mass of water = 1 kg

c1 = specific heat capacity of water = 4186 J/kg°C

m2 = mass of alcohol = 1.5 kg

c2 = specific heat capacity of alcohol = 2450 J/kg°C

Substitute the values into the equation:

1 * 4186 * (T - 45) = 1.5 * 2450 * (T - 20)

4186T - 188370 = 3675T - 73500

1189T = 114870

T = 96.6°C

Therefore, the final temperature of the mixture is 96.6°C.

Let the final temperature of the mixture be T.

Heat lost by water = Heat gained by alcohol

m1 * c1 * (T - 45) = m2 * c2 * (T - 20)

Where,

m1 = mass of water = 1 kg

c1 = specific heat capacity of water = 4186 J/kg°C

m2 = mass of alcohol = 1.5 kg

c2 = specific heat capacity of alcohol = 2450 J/kg°C

Substitute the values into the equation:

1 * 4186 * (T - 45) = 1.5 * 2450 * (T - 20)

4186T - 188370 = 3675T - 73500

1189T = 114870

T = 96.6°C

Therefore, the final temperature of the mixture is 96.6°C.