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2^3x =10?
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Feb 19
To solve for x in the equation 2^(3x) = 10, we need to first isolate the exponential term.
Taking the natural logarithm of both sides, we get:
ln(2^(3x)) = ln(10)
Using the property of logarithms that ln(a^b) = b*ln(a), we can rewrite the left side of the equation as:
3x*ln(2) = ln(10)
Now, divide both sides by ln(2) to solve for x:
3x = ln(10) / ln(2)
x = (ln(10) / ln(2)) / 3
x ≈ 1.660964
Therefore, x is approximately 1.660964.
Taking the natural logarithm of both sides, we get:
ln(2^(3x)) = ln(10)
Using the property of logarithms that ln(a^b) = b*ln(a), we can rewrite the left side of the equation as:
3x*ln(2) = ln(10)
Now, divide both sides by ln(2) to solve for x:
3x = ln(10) / ln(2)
x = (ln(10) / ln(2)) / 3
x ≈ 1.660964
Therefore, x is approximately 1.660964.
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