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2^3x =10?

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Feb 19

To solve for x in the equation 2^(3x) = 10, we need to first isolate the exponential term.

Taking the natural logarithm of both sides, we get:

ln(2^(3x)) = ln(10)

Using the property of logarithms that ln(a^b) = b*ln(a), we can rewrite the left side of the equation as:

3x*ln(2) = ln(10)

Now, divide both sides by ln(2) to solve for x:

3x = ln(10) / ln(2)

x = (ln(10) / ln(2)) / 3

x ≈ 1.660964

Therefore, x is approximately 1.660964.

Taking the natural logarithm of both sides, we get:

ln(2^(3x)) = ln(10)

Using the property of logarithms that ln(a^b) = b*ln(a), we can rewrite the left side of the equation as:

3x*ln(2) = ln(10)

Now, divide both sides by ln(2) to solve for x:

3x = ln(10) / ln(2)

x = (ln(10) / ln(2)) / 3

x ≈ 1.660964

Therefore, x is approximately 1.660964.