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Jan 20

To solve the quadratic equation 3x^2 + 17x + 10 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this equation, a = 3, b = 17, and c = 10.

Plugging in these values, we get:

x = (-(17) ± √((17)^2 - 4(3)(10))) / (2(3))

Simplifying further:

x = (-17 ± √(289 - 120)) / 6

x = (-17 ± √169) / 6

x = (-17 ± 13) / 6

This gives us two possible solutions:

x = (-17 + 13) / 6 = -4 / 6 = -2/3

x = (-17 - 13) / 6 = -30 / 6 = -5

Therefore, the solutions to the equation 3x^2 + 17x + 10 = 0 are x = -2/3 and x = -5.

x = (-b ± √(b^2 - 4ac)) / (2a)

In this equation, a = 3, b = 17, and c = 10.

Plugging in these values, we get:

x = (-(17) ± √((17)^2 - 4(3)(10))) / (2(3))

Simplifying further:

x = (-17 ± √(289 - 120)) / 6

x = (-17 ± √169) / 6

x = (-17 ± 13) / 6

This gives us two possible solutions:

x = (-17 + 13) / 6 = -4 / 6 = -2/3

x = (-17 - 13) / 6 = -30 / 6 = -5

Therefore, the solutions to the equation 3x^2 + 17x + 10 = 0 are x = -2/3 and x = -5.

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