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#chemistry
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#thermodynamics
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4.0 moles of argon gas is contained in a cylinder at 300k.How much heat must be added to raise its temperature to 600K at constant volume?
Anonymous
Apr 8
4.0 moles of argon gas is contained in a cylinder at 300k.How much heat must be added to raise its temperature to 600K at constant volume?
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Apr 8
To calculate the heat required to raise the temperature of the argon gas from 300K to 600K at constant volume, we can use the formula:
Q = n*Cv*ΔT
Where:
Q = heat added
n = number of moles of gas (4.0 moles)
Cv = molar specific heat at constant volume for argon gas (12.5 J/mol*K)
ΔT = change in temperature (600K - 300K = 300K)
Plugging in the values:
Q = 4.0 moles * 12.5 J/mol*K * 300K
Q = 1500 J
Therefore, 1500 Joules of heat must be added to raise the temperature of 4.0 moles of argon gas from 300K to 600K at constant volume.
Q = n*Cv*ΔT
Where:
Q = heat added
n = number of moles of gas (4.0 moles)
Cv = molar specific heat at constant volume for argon gas (12.5 J/mol*K)
ΔT = change in temperature (600K - 300K = 300K)
Plugging in the values:
Q = 4.0 moles * 12.5 J/mol*K * 300K
Q = 1500 J
Therefore, 1500 Joules of heat must be added to raise the temperature of 4.0 moles of argon gas from 300K to 600K at constant volume.
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