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#materials-science
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#thermodynamics
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#physics
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A 500mlong aluminium table expands when it was placed under the sun , it's temperature increases from 20°c to 60°c .what is the new length (linear expansivity of aluminum is 2.30*10^-5k)?

Mar 24

Cal

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Mar 24

First, we need to calculate the change in temperature:

ΔT = 60°C - 20°C = 40°C

Next, we can use the formula for linear expansion:

ΔL = α * L * ΔT

Where:

ΔL = change in length

α = linear expansivity of aluminum = 2.30 * 10^-5 K^-1

L = original length = 500 mm = 0.5 m

ΔT = change in temperature = 40°C

Now, we can plug in the values:

ΔL = 2.30 * 10^-5 * 0.5 * 40

ΔL = 2.30 * 10^-5 * 0.5 * 40

ΔL = 4.60 * 10^-5 * 40

ΔL = 0.000184 * 40

ΔL = 0.00736 m

Finally, we can find the new length by adding the change in length to the original length:

New length = 0.5 + 0.00736

New length = 0.50736 m

Therefore, the new length of the aluminum table after being placed under the sun is 0.50736 meters.

ΔT = 60°C - 20°C = 40°C

Next, we can use the formula for linear expansion:

ΔL = α * L * ΔT

Where:

ΔL = change in length

α = linear expansivity of aluminum = 2.30 * 10^-5 K^-1

L = original length = 500 mm = 0.5 m

ΔT = change in temperature = 40°C

Now, we can plug in the values:

ΔL = 2.30 * 10^-5 * 0.5 * 40

ΔL = 2.30 * 10^-5 * 0.5 * 40

ΔL = 4.60 * 10^-5 * 40

ΔL = 0.000184 * 40

ΔL = 0.00736 m

Finally, we can find the new length by adding the change in length to the original length:

New length = 0.5 + 0.00736

New length = 0.50736 m

Therefore, the new length of the aluminum table after being placed under the sun is 0.50736 meters.