A bird flew from town a to town b at steady speed of 80km/hr and back to town a at 90km/hr. If the forward journey took 20mins more by return journey. How far is town a from town b?

Let the distance between town A and town B be x km.

Time taken for the forward journey = x/80 hours
Time taken for the return journey = x/90 hours

According to the given information, the forward journey took 20 minutes (1/3 hours) more than the return journey. So, we can write the equation:

x/80 = x/90 + 1/3

Solving this equation, we get:

9x = 8x + 720
x = 720 km

Therefore, town A is 720 km away from town B.

Let the distance between town a and b be x km.
Time taken to travel from town a to b = x/80 hours
Time taken to travel from town b to a =x/90 hours
It is given that the forward journey took 20 mins more by return journey.
Therefore, x/80 - x/90 = 20/60
= (9x - 8x)/720 = 1/3
= x/720 = 1/3
= x = 720/3 = 240km
Therefore, the distance between town a and b is 240km