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#fluid-mechanics
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#physics
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A body of 10N in air and 8N when completely immersed in water .Neglecting the upthrust on air determine the weight of the body in the liquid of density 1.5g/cm3?
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Jul 1

Physics?

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Anonymous

Jul 3

To determine the weight of the body in the liquid, we need to consider the buoyant force acting on it when immersed in the liquid. The buoyant force is equal to the weight of the liquid displaced by the body.
Given that the weight of the body in the air is 10N and the weight of the body when completely immersed in water is 8N, we can conclude that the buoyant force acting on the body when immersed in water is 2N (10N - 8N).
To find the weight of the body in the liquid, we need to equate the buoyant force to the weight of the liquid displaced. The weight of the liquid displaced is equal to the volume of the liquid displaced multiplied by the density of the liquid (ρ) and the acceleration due to gravity (g).
Let's assume the volume of the liquid displaced by the body is V. We can use the formula:
Buoyant force = Weight of the liquid displaced
2N = V * ρ * g
Given that the density of the liquid (ρ) is 1.5 g/cm³, we need to convert it to SI units:
ρ = 1.5 g/cm³ = 1500 kg/m³ (since 1 g/cm³ = 1000 kg/m³)
The acceleration due to gravity (g) is approximately 9.8 m/s².
Substituting the values into the equation:
2N = V * 1500 kg/m³ * 9.8 m/s²
Now, we can solve for the volume of the liquid displaced (V):
V = 2N / (1500 kg/m³ * 9.8 m/s²)
V ≈ 0.000137 m³
Finally, to find the weight of the body in the liquid, we can calculate the weight of the liquid displaced:
Weight of the body in the liquid = Volume of the liquid displaced * Density of the liquid * Acceleration due to gravity
Weight of the body in the liquid ≈ 0.000137 m³ * 1500 kg/m³ * 9.8 m/s²
Weight of the body in the liquid ≈ 2.027 N
Therefore, the weight of the body in the liquid of density 1.5 g/cm³ (or 1500 kg/m³) is approximately 2.027 N.

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