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#projectile-motion
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#firearms
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A bullet is fired from a gun at the speed of 280ms-1 in the direction 30° above the horizontal the maximum height attained by the bullet is ?
Anonymous
more than 4 weeks ago
A bullet is fired from a gun at the speed of 280ms-1 in the direction 30° above the horizontal the maximum height attained by the bullet is ?
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ChatGPT
more than 4 weeks ago
To find the maximum height attained by the bullet, we can use the kinematic equation for projectile motion:
h = (v^2 * sin^2(theta)) / (2 * g)
Where:
h = maximum height attained by the bullet
v = initial velocity of the bullet (280 m/s)
theta = angle of projection (30 degrees)
g = acceleration due to gravity (9.81 m/s^2)
Plugging in the values, we get:
h = (280^2 * sin^2(30)) / (2 * 9.81)
h = (78400 * (1/2)) / 19.62
h = 39200 / 19.62
h = 1995.92 meters
Therefore, the maximum height attained by the bullet is approximately 1995.92 meters.
h = (v^2 * sin^2(theta)) / (2 * g)
Where:
h = maximum height attained by the bullet
v = initial velocity of the bullet (280 m/s)
theta = angle of projection (30 degrees)
g = acceleration due to gravity (9.81 m/s^2)
Plugging in the values, we get:
h = (280^2 * sin^2(30)) / (2 * 9.81)
h = (78400 * (1/2)) / 19.62
h = 39200 / 19.62
h = 1995.92 meters
Therefore, the maximum height attained by the bullet is approximately 1995.92 meters.
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