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#projectile-motion
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#firearms
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#physics
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A bullet is fired from a gun at the speed of 280ms-1 in the direction 30° above the horizontal the maximum height attained by the bullet is ?

Mar 26

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Mar 26

To find the maximum height attained by the bullet, we can use the kinematic equation for projectile motion:

h = (v^2 * sin^2(theta)) / (2 * g)

Where:

h = maximum height attained by the bullet

v = initial velocity of the bullet (280 m/s)

theta = angle of projection (30 degrees)

g = acceleration due to gravity (9.81 m/s^2)

Plugging in the values, we get:

h = (280^2 * sin^2(30)) / (2 * 9.81)

h = (78400 * (1/2)) / 19.62

h = 39200 / 19.62

h = 1995.92 meters

Therefore, the maximum height attained by the bullet is approximately 1995.92 meters.

h = (v^2 * sin^2(theta)) / (2 * g)

Where:

h = maximum height attained by the bullet

v = initial velocity of the bullet (280 m/s)

theta = angle of projection (30 degrees)

g = acceleration due to gravity (9.81 m/s^2)

Plugging in the values, we get:

h = (280^2 * sin^2(30)) / (2 * 9.81)

h = (78400 * (1/2)) / 19.62

h = 39200 / 19.62

h = 1995.92 meters

Therefore, the maximum height attained by the bullet is approximately 1995.92 meters.