A car travels 60m/s East and then 80m/s south.What is the magnitude of the resultant velocity of the car?

To find the magnitude of the resultant velocity of the car, we can use the Pythagorean theorem since the velocities are at right angles to each other.

Let's denote the velocity of the car traveling east as V1 = 60 m/s and the velocity of the car traveling south as V2 = 80 m/s.

The magnitude of the resultant velocity (Vr) can be calculated as:

Vr = √(V1^2 + V2^2)
Vr = √(60^2 + 80^2)
Vr = √(3600 + 6400)
Vr = √10000
Vr = 100 m/s

Therefore, the magnitude of the resultant velocity of the car is 100 m/s.

$$\overrightarrow v=60\overrightarrow i+80\overrightarrow j$$

$$v=\sqrt{60^2+80^2}=\sqrt{10000}=100m/s$$