A cylinder has a capacity of 0.03m³ and contains a mixture of saturated water and steam at a temperature of 235⁰c. The mass of a liquid is 8kg. Determine the pressure, mass and specific volume?

Given:
- Volume of the cylinder (V) = 0.03 m³
- Temperature (T) = 235⁰C = 508K
- Mass of liquid (m) = 8kg

To determine the pressure, mass, and specific volume, we can use the steam tables for water at 235⁰C (508K).

1. Determine the specific volume of the mixture:
From the steam tables, at 235⁰C, the specific volume of saturated water is approximately 0.00104 m³/kg.
Since the volume of the cylinder is 0.03 m³ and the mass of liquid is 8kg, the specific volume of the mixture can be calculated as:
Specific volume = Volume / Mass = 0.03 m³ / 8kg = 0.00375 m³/kg

2. Determine the quality of the mixture:
Quality (x) = (Specific volume - Specific volume of saturated liquid) / (Specific volume of saturated vapor - Specific volume of saturated liquid)
Quality (x) = (0.00375 - 0.00104) / (0.885 - 0.00104) = 0.00271

3. Determine the pressure:
From the steam tables, at 235⁰C, the pressure corresponding to the quality of 0.00271 is approximately 0.2 MPa.

4. Determine the mass of the mixture:
Since the mass of liquid is 8kg, the mass of the mixture can be calculated as:
Mass of mixture = Mass of liquid / Quality = 8kg / 0.00271 = 2952.38 kg

Therefore, the pressure in the cylinder is 0.2 MPa, the mass of the mixture is 2952.38 kg, and the specific volume of the mixture is 0.00375 m³/kg.