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#mathematics
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#physics
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A falling stone takes 0.28s to travel past a window 2.2m . From what height above the top of window did the stone fall ?

Apr 15

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Apr 15

To find the height from which the stone fell, we can use the equation of motion:

s = ut + (1/2)at^2

Where:

s = distance traveled by the stone (2.2m)

u = initial velocity of the stone (0 m/s, as the stone is falling)

a = acceleration due to gravity (-9.8 m/s^2)

t = time taken for the stone to travel past the window (0.28s)

Plugging in the values, we get:

2.2 = 0 + (1/2)(-9.8)(0.28)^2

2.2 = -1.3728

2.2 = -1.3728

Therefore, the stone fell from a height of 2.2m above the top of the window.

s = ut + (1/2)at^2

Where:

s = distance traveled by the stone (2.2m)

u = initial velocity of the stone (0 m/s, as the stone is falling)

a = acceleration due to gravity (-9.8 m/s^2)

t = time taken for the stone to travel past the window (0.28s)

Plugging in the values, we get:

2.2 = 0 + (1/2)(-9.8)(0.28)^2

2.2 = -1.3728

2.2 = -1.3728

Therefore, the stone fell from a height of 2.2m above the top of the window.