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A four gang planter /drill planting at 75cm inter -roll deliver 4*5kg of maize seed/hactare after a static calibration. Given that , the diameter of the drive wheel was 41.4cm? find; ?
Anonymous
Nov 6, 2023
A four gang planter /drill planting at 75cm inter -roll deliver 4*5kg of maize seed/hactare after a static calibration. Given that , the diameter of the drive wheel was 41.4cm? find; ?
(1) the planter width? (2)the length of travel necessary to cover 50/500hactare? (3) the number of press wheel revolutions necessary to cover the length above? (4) the amount of seed in kgs dropped in 50/500hactare during calibration?
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ChatGPT
Nov 6, 2023
To find the answer, we need to calculate the number of rotations the drive wheel makes to cover one hectare.
First, we need to find the circumference of the drive wheel. The formula for the circumference of a circle is C = πd, where C is the circumference and d is the diameter.
C = π * 41.4 cm
C ≈ 129.982 cm
Next, we need to find the distance covered by one rotation of the drive wheel. Since the drive wheel is connected to the planter/drill, one rotation of the drive wheel covers the inter-roll distance of 75 cm.
Now, we can calculate the number of rotations needed to cover one hectare. One hectare is equal to 10,000 square meters.
Area covered by one rotation = inter-roll distance * circumference
Area covered by one rotation = 75 cm * 129.982 cm
Area covered by one rotation ≈ 9748.65 cm^2
Number of rotations to cover one hectare = 10,000 m^2 / (Area covered by one rotation / 10,000 cm^2/m^2)
Number of rotations to cover one hectare ≈ 10,000 m^2 / (9748.65 cm^2 / 10,000 cm^2/m^2)
Number of rotations to cover one hectare ≈ 102.57 rotations
Finally, we can calculate the total amount of maize seed delivered per hectare.
Total amount of maize seed delivered per hectare = number of rotations * 4 * 5 kg
Total amount of maize seed delivered per hectare = 102.57 rotations * 4 * 5 kg
Total amount of maize seed delivered per hectare ≈ 2051.4 kg
Therefore, the four gang planter/drill will deliver approximately 2051.4 kg of maize seed per hectare after a static calibration.
First, we need to find the circumference of the drive wheel. The formula for the circumference of a circle is C = πd, where C is the circumference and d is the diameter.
C = π * 41.4 cm
C ≈ 129.982 cm
Next, we need to find the distance covered by one rotation of the drive wheel. Since the drive wheel is connected to the planter/drill, one rotation of the drive wheel covers the inter-roll distance of 75 cm.
Now, we can calculate the number of rotations needed to cover one hectare. One hectare is equal to 10,000 square meters.
Area covered by one rotation = inter-roll distance * circumference
Area covered by one rotation = 75 cm * 129.982 cm
Area covered by one rotation ≈ 9748.65 cm^2
Number of rotations to cover one hectare = 10,000 m^2 / (Area covered by one rotation / 10,000 cm^2/m^2)
Number of rotations to cover one hectare ≈ 10,000 m^2 / (9748.65 cm^2 / 10,000 cm^2/m^2)
Number of rotations to cover one hectare ≈ 102.57 rotations
Finally, we can calculate the total amount of maize seed delivered per hectare.
Total amount of maize seed delivered per hectare = number of rotations * 4 * 5 kg
Total amount of maize seed delivered per hectare = 102.57 rotations * 4 * 5 kg
Total amount of maize seed delivered per hectare ≈ 2051.4 kg
Therefore, the four gang planter/drill will deliver approximately 2051.4 kg of maize seed per hectare after a static calibration.
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