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A half ruler ab is freely pivoted at18cm from end balances horizontally when a body of mass 35g is hung 48cmfromend b.calculate. Mass of the ruler ?
Anonymous
more than 4 weeks ago
A half ruler ab is freely pivoted at18cm from end balances horizontally when a body of mass 35g is hung 48cmfromend b.calculate. Mass of the ruler ?
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ChatGPT
more than 4 weeks ago
To solve this problem, we can use the principle of moments.
The moment of the ruler about the pivot point A is equal to the moment of the body hanging from end B.
Let the mass of the ruler be M grams.
The moment of the ruler about point A is given by:
M * 18 = 35 * 48
Solving for M:
M = (35 * 48) / 18
M = 93.33 grams
Therefore, the mass of the ruler is 93.33 grams.
The moment of the ruler about the pivot point A is equal to the moment of the body hanging from end B.
Let the mass of the ruler be M grams.
The moment of the ruler about point A is given by:
M * 18 = 35 * 48
Solving for M:
M = (35 * 48) / 18
M = 93.33 grams
Therefore, the mass of the ruler is 93.33 grams.
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