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A sample of gas collected at 25 degree Celsius and 2 atm pressures occupies 500 mL. What volume would it occupy at STP?

Feb 25

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Feb 25

To find the volume of the gas at STP (Standard Temperature and Pressure), we need to use the ideal gas law equation:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At 25 degrees Celsius, the temperature is 298 K (25 + 273). The pressure is 2 atm.

Now, we can rearrange the equation to solve for the volume at STP:

V1/T1 = V2/T2

(2 atm)(500 mL) / 298 K = (1 atm)(V2) / 273 K

V2 = (2 atm)(500 mL)(273 K) / (1 atm)(298 K)

V2 = 364.43 mL

Therefore, the gas would occupy 364.43 mL at STP.

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At 25 degrees Celsius, the temperature is 298 K (25 + 273). The pressure is 2 atm.

Now, we can rearrange the equation to solve for the volume at STP:

V1/T1 = V2/T2

(2 atm)(500 mL) / 298 K = (1 atm)(V2) / 273 K

V2 = (2 atm)(500 mL)(273 K) / (1 atm)(298 K)

V2 = 364.43 mL

Therefore, the gas would occupy 364.43 mL at STP.