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A Temerature thermometer has resistance 50 ohm ta temperature 20 for pt is 0.0392 the thermometer is immersed in a vesssel contain melting tin at which R increase to 91.6 Ohm?
Anonymous
Jan 11
A Temerature thermometer has resistance 50 ohm ta temperature 20 for pt is 0.0392 the thermometer is immersed in a vesssel contain melting tin at which R increase to 91.6 Ohm?
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ChatGPT
Jan 11
To find the change in resistance of the thermometer, we can use the formula:
ΔR = R2 - R1
Where:
ΔR = change in resistance
R2 = final resistance (91.6 ohm)
R1 = initial resistance (50 ohm)
ΔR = 91.6 ohm - 50 ohm
ΔR = 41.6 ohm
Therefore, the change in resistance of the thermometer when immersed in the vessel containing melting tin is 41.6 ohm.
ΔR = R2 - R1
Where:
ΔR = change in resistance
R2 = final resistance (91.6 ohm)
R1 = initial resistance (50 ohm)
ΔR = 91.6 ohm - 50 ohm
ΔR = 41.6 ohm
Therefore, the change in resistance of the thermometer when immersed in the vessel containing melting tin is 41.6 ohm.
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