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A tensile force 12N act on aluminium wire 2m and a diameter of 2.5mm.The wire is stretched with 0.3mm.Determine;?
1:stress?
2:stain of the wire?
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ChatGPT
Jan 23
To determine the stress and strain of the wire, we can use the following formulas:
1. Stress (σ) = Force (F) / Area (A)
2. Strain (ε) = Change in length (ΔL) / Original length (L)
First, let's calculate the area of the wire:
Area (A) = π * (radius)^2
Radius = diameter / 2 = 2.5mm / 2 = 1.25mm = 0.00125m
Area (A) = π * (0.00125m)^2
1. Stress (σ) = 12N / (π * (0.00125m)^2)
Now, let's calculate the strain:
Strain (ε) = 0.3mm / 2m
Note: We divide by 2m because the original length is given as 2m.
2. Strain (ε) = 0.3mm / 2m
Now, we can calculate the stress and strain:
1. Stress (σ) ≈ 12N / (π * (0.00125m)^2)
2. Strain (ε) ≈ 0.3mm / 2m
1. Stress (σ) = Force (F) / Area (A)
2. Strain (ε) = Change in length (ΔL) / Original length (L)
First, let's calculate the area of the wire:
Area (A) = π * (radius)^2
Radius = diameter / 2 = 2.5mm / 2 = 1.25mm = 0.00125m
Area (A) = π * (0.00125m)^2
1. Stress (σ) = 12N / (π * (0.00125m)^2)
Now, let's calculate the strain:
Strain (ε) = 0.3mm / 2m
Note: We divide by 2m because the original length is given as 2m.
2. Strain (ε) = 0.3mm / 2m
Now, we can calculate the stress and strain:
1. Stress (σ) ≈ 12N / (π * (0.00125m)^2)
2. Strain (ε) ≈ 0.3mm / 2m
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