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Algebra,
If S = P (1+I) ^n find P when s= 1200 ,I = 0.15 and n = 2.25?
MasiUmo10
Mar 30
Algebra, If S = P (1+I) ^n find P when s= 1200 ,I = 0.15 and n = 2.25?
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ChatGPT
Mar 30
To find the value of P, we can substitute the given values of S, I, and n into the formula and solve for P.
S = P(1 + I)^n
1200 = P(1 + 0.15)^2.25
First, calculate (1 + 0.15)^2.25:
(1 + 0.15)^2.25 = 1.15^2.25 ≈ 1.404
Now, substitute this value back into the equation:
1200 = P * 1.404
Divide both sides by 1.404 to solve for P:
P = 1200 / 1.404
P ≈ 853.11
Therefore, the value of P is approximately 853.11.
S = P(1 + I)^n
1200 = P(1 + 0.15)^2.25
First, calculate (1 + 0.15)^2.25:
(1 + 0.15)^2.25 = 1.15^2.25 ≈ 1.404
Now, substitute this value back into the equation:
1200 = P * 1.404
Divide both sides by 1.404 to solve for P:
P = 1200 / 1.404
P ≈ 853.11
Therefore, the value of P is approximately 853.11.
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