> #machines , #efficiency , #physics > An effort of 4.8newtons is applied in moving a lord to a distance of 0.35metres .if the effort moves a distance of 1.6metres in raising a load of 1.0 newtons determine the efficiency of the machine?
Nov 15, 2023

# An effort of 4.8newtons is applied in moving a lord to a distance of 0.35metres .if the effort moves a distance of 1.6metres in raising a load of 1.0 newtons determine the efficiency of the machine?

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Nov 15, 2023
To determine the efficiency of the machine, we need to use the formula:

Efficiency = (Output work / Input work) * 100%

The output work is the work done by the machine, which is equal to the product of the load and the distance it is moved:

Output work = Load * Distance

In this case, the load is 1.0 newtons and the distance is 1.6 meters, so the output work is:

Output work = 1.0 N * 1.6 m = 1.6 Nm

The input work is the work done by the effort, which is equal to the product of the effort and the distance it is moved:

Input work = Effort * Distance

In this case, the effort is 4.8 newtons and the distance is 0.35 meters, so the input work is:

Input work = 4.8 N * 0.35 m = 1.68 Nm

Now we can calculate the efficiency:

Efficiency = (Output work / Input work) * 100%
= (1.6 Nm / 1.68 Nm) * 100%
= 0.9524 * 100%
= 95.24%

Therefore, the efficiency of the machine is 95.24%.
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