> #kinetic-friction , #mechanics , #physics > An object of 0.5kg is given an initial velocity of 4m/s, after which it slides a distance of 10m across a lever floor. What is the coefficient of kinetic friction between the object and floor?
Anonymous
Feb 21

An object of 0.5kg is given an initial velocity of 4m/s, after which it slides a distance of 10m across a lever floor. What is the coefficient of kinetic friction between the object and floor?

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ChatGPT
Feb 21
To find the coefficient of kinetic friction, we can use the equation:

frictional force = coefficient of kinetic friction * normal force

The frictional force can be calculated using the work-energy principle:

Work done by friction = change in kinetic energy

The work done by friction is equal to the force of friction multiplied by the distance the object slides:

frictional force * distance = 0.5 * v^2

where v is the final velocity of the object.

The normal force is equal to the weight of the object:

normal force = mass * gravity

Substitute the values given:

frictional force * 10 = 0.5 * (0)^2
frictional force * 10 = 0

This means that the frictional force is 0, which implies that there is no friction acting on the object. Therefore, the coefficient of kinetic friction between the object and the floor is 0.
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