Calculate the charge, energy stored in each capacitor and also the potential difference across each capacitors ?

To calculate the charge, energy stored, and potential difference across each capacitor, we need to know the capacitance (C) and the voltage (V) applied to the circuit.

Let's assume we have three capacitors connected in series with capacitances C1, C2, and C3, and a total voltage V applied to the circuit.

1. Charge on each capacitor:
The charge on each capacitor can be calculated using the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage.

For capacitor 1: Q1 = C1 * V
For capacitor 2: Q2 = C2 * V
For capacitor 3: Q3 = C3 * V

2. Energy stored in each capacitor:
The energy stored in each capacitor can be calculated using the formula U = 0.5 * C * V^2, where U is the energy stored, C is the capacitance, and V is the voltage.

For capacitor 1: U1 = 0.5 * C1 * V^2
For capacitor 2: U2 = 0.5 * C2 * V^2
For capacitor 3: U3 = 0.5 * C3 * V^2

3. Potential difference across each capacitor:
The potential difference across each capacitor can be calculated using the formula V = Q / C, where V is the potential difference, Q is the charge, and C is the capacitance.

For capacitor 1: V1 = Q1 / C1
For capacitor 2: V2 = Q2 / C2
For capacitor 3: V3 = Q3 / C3

By using the above formulas and the given values of capacitances and voltage, you can calculate the charge, energy stored, and potential difference across each capacitor in the circuit.

Circuit:

- Capacitor C1 = 20 μF
- Capacitor C2 = 30 μF
- Battery voltage V = 12 V

Charge on Capacitors:

The total charge stored in the capacitors is:

```
Q = CV
```

where Q is the charge, C is the capacitance, and V is the voltage.

For capacitor C1:

```
Q1 = C1V = 20 μF × 12 V = 240 μC
```

For capacitor C2:

```
Q2 = C2V = 30 μF × 12 V = 360 μC
```

Energy Stored in Capacitors:

The energy stored in a capacitor is given by:

```
E = 1/2 - CV^2
```

where E is the energy, C is the capacitance, and V is the voltage.

For capacitor C1:

```
E1 = 1/2 - C1V^2 = 1/2 - 20 μF - (12 V)^2 = 144 μJ
```

For capacitor C2:

```
E2 = 1/2 - C2V^2 = 1/2 - 30 μF - (12 V)^2 = 216 μJ
```

Potential Difference across Capacitors:

Since the capacitors are connected in parallel, they have the same potential difference across them. This potential difference is equal to the battery voltage:

```
V1 = V2 = V = 12 V
```