Calculate the mass of 6.02×10^23 i2.

To calculate the mass of 6.02×10^23 i2 (iodine molecules), we first need to determine the molar mass of iodine (I2).

The molar mass of iodine (I2) is 253.8 g/mol.

Now, we can calculate the mass of 6.02×10^23 i2 molecules:

Mass = (6.02×10^23) x (253.8 g/mol)
Mass = 1.52×10^26 g

Therefore, the mass of 6.02×10^23 i2 molecules is 1.52×10^26 grams.

The mass of one ion of i2 is given by the molar mass of i2 divided by the Avogadro constant:

$$m = \frac{M}{N_A}$$

where:

- m is the mass of one ion of i2 in grams
- M is the molar mass of i2 in grams per mole
- N_A is the Avogadro constant in ions per mole

The molar mass of i2 is 253.80 g/mol. The Avogadro constant is 6.022×10^23 ions/mol. Therefore, the mass of one ion of i2 is:

$$m = \frac{253.80 g/mol}{6.022×10^23 ions/mol} = 4.216×10^-23 g$$

The mass of 6.02×10^23 ions of i2 is:

$$m = 6.02×10^23 ions × 4.216×10^-23 g/ion = 25.42 g$$