Calculate the molarity of a solution prepared by dissolving 10 grams of HC1 in enough water to make 500mL of solution.( Molar mass of HC1=36.46g/mol)?

First, we need to calculate the number of moles of HCl in 10 grams:

Number of moles = mass / molar mass
Number of moles = 10g / 36.46g/mol
Number of moles = 0.274 moles

Next, we need to calculate the volume of the solution in liters:

Volume = 500mL = 0.5L

Now, we can calculate the molarity of the solution:

Molarity = moles / volume
Molarity = 0.274 moles / 0.5L
Molarity = 0.548 mol/L

Therefore, the molarity of the solution is 0.548 mol/L.

Molarity (M) = Moles of solute / Volume of solution in liters

Step 1: Convert the mass of HCl to moles
Moles of HCl = Mass / Molar mass
Moles of HCl = 10 g / 36.46 g/mol
Moles of HCl = 0.2743 mol

Step 2: Convert the volume of solution to liters
Volume of solution = 500 mL
Volume of solution = 500 mL - (1 L / 1000 mL)
Volume of solution = 0.5 L

Step 3: Calculate the molarity
Molarity = Moles of solute / Volume of solution in liters
Molarity = 0.2743 mol / 0.5 L
Molarity = 0.5486 M

Therefore, the molarity of the solution is 0.5486 M.