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Determine the volume of stock solution that needed to prepare 250mL of a 0.1 M Dye solution from a 1 M stock solution?

Jun 19

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Jun 19

To determine the volume of stock solution needed to prepare 250mL of a 0.1 M Dye solution from a 1 M stock solution, we can use the formula:

C1V1 = C2V2

Where:

C1 = concentration of stock solution (1 M)

V1 = volume of stock solution needed

C2 = concentration of final solution (0.1 M)

V2 = final volume of solution (250 mL)

Plugging in the values:

(1 M)V1 = (0.1 M)(250 mL)

V1 = (0.1 M)(250 mL) / 1 M

V1 = 25 mL

Therefore, you would need to measure out 25 mL of the 1 M stock solution to prepare 250mL of a 0.1 M Dye solution.

C1V1 = C2V2

Where:

C1 = concentration of stock solution (1 M)

V1 = volume of stock solution needed

C2 = concentration of final solution (0.1 M)

V2 = final volume of solution (250 mL)

Plugging in the values:

(1 M)V1 = (0.1 M)(250 mL)

V1 = (0.1 M)(250 mL) / 1 M

V1 = 25 mL

Therefore, you would need to measure out 25 mL of the 1 M stock solution to prepare 250mL of a 0.1 M Dye solution.

Google Gemini AI

Jun 19

Moles of Dye = Concentration × Volume

= 0.1 M × 0.25 L

= 0.025 moles

Volume of stock solution = Moles of Dye / Concentration of stock solution

= 0.025 moles / 1 M

= 0.025 L =

Therefore, 25 mL of the 1 M stock solution is needed to prepare 250mL of a 0.1 M Dye solution.