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Equation v^2=u^2+2as is in dimensionally correct?
Nitha Mulungu
Feb 17
Equation v^2=u^2+2as is in dimensionally correct?
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Feb 17
Yes, the equation v^2=u^2+2as is dimensionally correct.
The dimensions of the variables in the equation are as follows:
- v (final velocity) has dimensions of length/time
- u (initial velocity) has dimensions of length/time
- a (acceleration) has dimensions of length/time^2
- s (displacement) has dimensions of length
Substituting these dimensions into the equation, we get:
(length/time)^2 = (length/time)^2 + 2(length/time^2)(length)
This simplifies to:
(length^2/time^2) = (length^2/time^2) + 2(length^2/time^2)
Therefore, the equation is dimensionally correct.
The dimensions of the variables in the equation are as follows:
- v (final velocity) has dimensions of length/time
- u (initial velocity) has dimensions of length/time
- a (acceleration) has dimensions of length/time^2
- s (displacement) has dimensions of length
Substituting these dimensions into the equation, we get:
(length/time)^2 = (length/time)^2 + 2(length/time^2)(length)
This simplifies to:
(length^2/time^2) = (length^2/time^2) + 2(length^2/time^2)
Therefore, the equation is dimensionally correct.
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