Factorize x² + x - 12 Factor out the HCF of the first group ?

To factorize x² + x - 12, we first need to find two numbers that multiply to -12 and add up to 1 (the coefficient of the x term).

The two numbers that satisfy this condition are 4 and -3.

Therefore, we can rewrite the expression as:

x² + 4x - 3x - 12

Now, we can factor out the HCF of the first group, which is x:

x(x + 4) - 3(x + 4)

Now, we can factor out the common binomial factor of (x + 4):

(x + 4)(x - 3)

So, the factorization of x² + x - 12 is (x + 4)(x - 3).

x² - x - 12
HCF=1
=(x)²--(1)-(x)-12
=(x)²-(4)-(x)+(3)-(x)-12
=(x)²-4x+3x-12
Taking x common from the 1st two terms & 3 from the next two terms
=x(x-4)+3(x-4)
(x-4) is common
=(x-4)(x+3)