Find the 17th term of the Arithmetic Progression with first term 5 and common difference of 2?

To find the 17th term of an arithmetic progression, we can use the formula:

\[a_n = a_1 + (n-1)d\]

where:
- \(a_n\) is the nth term
- \(a_1\) is the first term
- \(d\) is the common difference
- \(n\) is the term number

Given that the first term \(a_1 = 5\), the common difference \(d = 2\), and we want to find the 17th term, we can plug these values into the formula:

\[a_{17} = 5 + (17-1) \times 2\]
\[a_{17} = 5 + 16 \times 2\]
\[a_{17} = 5 + 32\]
\[a_{17} = 37\]

Therefore, the 17th term of the arithmetic progression with first term 5 and common difference of 2 is 37.

The nth term of an arithmetic progression is given by the formula:

$$a_n = a_1 + (n-1)d$$

where:

- $$a_n$$ is the nth term
- $$a_1$$ is the first term
- n is the number of the term
- d is the common difference

Given:

- $$a_1 = 5$$
- d = 2
- n = 17

Substituting these values into the formula, we get:

$$a_{17} = 5 + (17-1)2$$
$$a_{17} = 5 + 16 \times 2$$
$$a_{17} = 5 + 32$$
$$a_{17} = 37$$

Therefore, the 17th term of the arithmetic progression is 37.