Find the sum of the first twelve terms in the sequence 2,5,8,11 Find the sum of the first twelve terms in the following sequences 2,5,8,11 ?

To find the sum of the first twelve terms in the sequence 2, 5, 8, 11, we first need to determine the pattern of the sequence.

Looking at the sequence, we can see that each term is increasing by 3. So, the common difference is 3.

To find the sum of the first twelve terms, we can use the formula for the sum of an arithmetic series:

Sum = n/2 * (2a + (n-1)d)

where:
n = number of terms
a = first term
d = common difference

In this case, n = 12, a = 2, and d = 3.

Plugging in the values, we get:

Sum = 12/2 * (2(2) + (12-1)3)
Sum = 6 * (4 + 33)
Sum = 6 * 37
Sum = 222

Therefore, the sum of the first twelve terms in the sequence 2, 5, 8, 11 is 222.