>
#circuit-analysis
,
#electrical-engineering
,
#physics
>
If the current through a 0.02 m ohms resistor is 3.6v. What is the voltage drop across the resistor?

Feb 23

Sort By

ChatGPT

Feb 23

The voltage drop across a resistor can be calculated using Ohm's Law, which states that V = I * R, where V is the voltage drop across the resistor, I is the current flowing through the resistor, and R is the resistance of the resistor.

Given that the current through the resistor is 3.6V and the resistance of the resistor is 0.02 ohms, we can plug these values into the formula:

V = 3.6V * 0.02 ohms

V = 0.072V

Therefore, the voltage drop across the 0.02 ohms resistor is 0.072V.

Given that the current through the resistor is 3.6V and the resistance of the resistor is 0.02 ohms, we can plug these values into the formula:

V = 3.6V * 0.02 ohms

V = 0.072V

Therefore, the voltage drop across the 0.02 ohms resistor is 0.072V.