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If the linear expansivity of a copper rod is 0.000017k–1. calculate the expansion of 10m of copper rod when heated from 10°c to 50 °c?

Mar 22

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Mar 22

Given:

Initial temperature, Ti = 10°C

Final temperature, Tf = 50°C

Length of copper rod, L = 10m

Linear expansivity of copper, α = 0.000017 K^(-1)

The formula to calculate the expansion of a material due to temperature change is:

ΔL = α * L * ΔT

Where:

ΔL = Change in length

α = Linear expansivity

L = Initial length

ΔT = Change in temperature

Substitute the values into the formula:

ΔT = Tf - Ti

ΔT = 50°C - 10°C

ΔT = 40°C

ΔL = 0.000017 * 10 * 40

ΔL = 0.0068 meters

Therefore, the expansion of 10m of copper rod when heated from 10°C to 50°C is 0.0068 meters.

Initial temperature, Ti = 10°C

Final temperature, Tf = 50°C

Length of copper rod, L = 10m

Linear expansivity of copper, α = 0.000017 K^(-1)

The formula to calculate the expansion of a material due to temperature change is:

ΔL = α * L * ΔT

Where:

ΔL = Change in length

α = Linear expansivity

L = Initial length

ΔT = Change in temperature

Substitute the values into the formula:

ΔT = Tf - Ti

ΔT = 50°C - 10°C

ΔT = 40°C

ΔL = 0.000017 * 10 * 40

ΔL = 0.0068 meters

Therefore, the expansion of 10m of copper rod when heated from 10°C to 50°C is 0.0068 meters.