If the linear expansivity of a copper rod is 0.000017k–1. calculate the expansion of 10m of copper rod when heated from 10°c to 50 °c?

Given:
Initial temperature, Ti = 10°C
Final temperature, Tf = 50°C
Length of copper rod, L = 10m
Linear expansivity of copper, α = 0.000017 K^(-1)

The formula to calculate the expansion of a material due to temperature change is:
ΔL = α * L * ΔT

Where:
ΔL = Change in length
α = Linear expansivity
L = Initial length
ΔT = Change in temperature

Substitute the values into the formula:
ΔT = Tf - Ti
ΔT = 50°C - 10°C
ΔT = 40°C

ΔL = 0.000017 * 10 * 40
ΔL = 0.0068 meters

Therefore, the expansion of 10m of copper rod when heated from 10°C to 50°C is 0.0068 meters.