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#programming
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If the second and the fifth terms of a geometric sequence.
Respectively, are 20%9 and 160%243,then find
A, the common ratio?
B,the first term ?
C,the (n+1)term ?
If the second and the fifth terms of a geometric sequence.
Respectively, are 20%9 and 160%243,then find
A, the common ratio?
B,the first term ?
C,the (n+1)term ?
Let's denote the first term of the geometric sequence as "a" and the common ratio as "r".
We are given that the second term is 20%9 and the fifth term is 160%243.
The second term can be written as a*r, and we have a*r = 20%9. The fifth term can be written as a*r^4, and we have a*r^4 = 160%243.
To find the common ratio "r", we can divide the equation for the fifth term by the equation for the second term: (a*r^4) / (a*r) = (160%243) / (20%9) r^3 = (160%243) / (20%9) r^3 = (160/243) / (20/9) r^3 = (160/243) * (9/20) r^3 = 12/27 r^3 = 4/9 r = (4/9)^(1/3)
To find the first term "a", we can substitute the value of "r" into the equation for the second term: a*r = 20%9 a*(4/9)^(1/3) = 20%9 a = (20%9) / ((4/9)^(1/3))
To find the (n+1)th term, we can use the formula for the nth term of a geometric sequence: a_n = a*r^(n-1) a_(n+1) = a*r^n
So, the (n+1)th term is a*(4/9)^n.
Unfortunately, without knowing the value of "n", we cannot determine the exact value of the (n+1)th term.