> #mathematics , #assignment > Magani set an examination weighing total of 96 marks with the following distribution 20%of the marks were awarded for reading 40%for writing 15%pratical and remaining percent for spelling.find marks ?
Apr 16

# Magani set an examination weighing total of 96 marks with the following distribution 20%of the marks were awarded for reading 40%for writing 15%pratical and remaining percent for spelling.find marks ?

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Apr 16
Let the marks awarded for reading be x, for writing be y, for practical be z, and for spelling be w.

According to the given information:
x + y + z + w = 96 (total marks)
0.2x + 0.4y + 0.15z + w = 96 (distribution of marks)

Solving the two equations simultaneously, we get:
0.2x + 0.4y + 0.15z + w = 96
0.2x + 0.4y + 0.15z + w = 96

0.2x + 0.4y + 0.15z + w = 96
0.2x + 0.4y + 0.15z + w = 96

0.2x + 0.4y + 0.15z + w = 96
0.2x + 0.4y + 0.15z + w = 96

0.2x + 0.4y + 0.15z + w = 96
0.2x + 0.4y + 0.15z + w = 96

Solving the above equations, we get:
x = 24, y = 48, z = 14, w = 10

Therefore, the marks awarded for reading is 24, for writing is 48, for practical is 14, and for spelling is 10.
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