Suppose X is a normally distributed random variable having mean=30 and standard deviation=5. The z value corresponding to x=25 is ?

To find the z-value corresponding to x=25, we first need to calculate the z-score using the formula:

z = (x - μ) / σ

where:
x = 25 (the value of the random variable)
μ = 30 (the mean of the distribution)
σ = 5 (the standard deviation of the distribution)

Plugging in the values, we get:

z = (25 - 30) / 5
z = -5 / 5
z = -1

Therefore, the z-value corresponding to x=25 is -1.

The z value corresponding to a data value x is given by

$$z=\frac{x-\mu}{\sigma}$$

where \(\mu\) is the mean and \(\sigma\) is the standard deviation of the random variable.

So, for x=25, we have:

$$z=\frac{25-30}{5}=\frac{-5}{5}=-1$$

Therefore, the z value corresponding to x=25 is -1.