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#mathematics
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#equations
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#in-mathematic-grade-11
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The solution set of the equation [2x+1]=10 is
A)[9/5,2)
B)[9/2,5]
C)(-infinity,9/2]
D)(-infinity, 9/2] union (5, infinity)?

Oct 29, 2023

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Oct 29, 2023

To solve the equation [2x+1]=10, we need to consider two cases: when 2x+1 is positive and when it is negative.

Case 1: 2x+1 is positive

When 2x+1 is positive, the equation becomes 2x+1=10. Solving for x, we have:

2x+1=10

2x=9

x=9/2

Case 2: 2x+1 is negative

When 2x+1 is negative, the equation becomes -(2x+1)=10. Solving for x, we have:

-(2x+1)=10

-2x-1=10

-2x=11

x=-11/2

Therefore, the solution set of the equation [2x+1]=10 is x in the interval (-infinity, -11/2] union [9/2, infinity).

The answer is D) (-infinity, 9/2] union (5, infinity).

Case 1: 2x+1 is positive

When 2x+1 is positive, the equation becomes 2x+1=10. Solving for x, we have:

2x+1=10

2x=9

x=9/2

Case 2: 2x+1 is negative

When 2x+1 is negative, the equation becomes -(2x+1)=10. Solving for x, we have:

-(2x+1)=10

-2x-1=10

-2x=11

x=-11/2

Therefore, the solution set of the equation [2x+1]=10 is x in the interval (-infinity, -11/2] union [9/2, infinity).

The answer is D) (-infinity, 9/2] union (5, infinity).

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