Transistor used in CE amplifier circuit when a signal of 30mV is added to base emitter voltage,the currentchanges by 30microA and collector current by mA.the load resistor 5Kohms.culculatecurrentgain?

To calculate the current gain of the CE amplifier circuit, we first need to determine the base current and collector current without the added signal.

Given:
- Change in base-emitter voltage (ΔVbe) = 30mV
- Change in collector current (ΔIc) = 1mA
- Change in base current (ΔIb) = 30μA
- Load resistor (RL) = 5kΩ

The current gain (β) of a transistor is defined as the ratio of collector current (Ic) to base current (Ib). Therefore, we can calculate the current gain using the following formula:

β = ΔIc / ΔIb

Given that ΔIc = 1mA and ΔIb = 30μA, we can substitute these values into the formula to find the current gain:

β = 1mA / 30μA
β = 1000 / 30
β = 33.33

Therefore, the current gain of the CE amplifier circuit is approximately 33.33.

Given:

- Signal added to base-emitter voltage: 30 mV
- Change in base current (ΔI_B): 30 μA
- Change in collector current (ΔI_C): x mA
- Load resistor (R_L): 5 kΩ

To find:

- Current gain (β)

Solution:

The current gain (β) of a CE amplifier circuit is defined as the ratio of change in collector current (ΔI_C) to the change in base current (ΔI_B):

```
β = ΔI_C / ΔI_B
```

We need to convert the given change in collector current from milliamps (mA) to microamps (μA):

```
ΔI_C = x mA - 1000 μA/mA = 1000x μA
```

Substituting the given values into the formula:

```
β = 1000x μA / 30 μA = 1000x / 3 = 333.33x
```

Since the value of x is not given, the current gain (β) cannot be determined exactly. However, we can express it as a multiple of 333.33, which represents the current gain for a change in collector current of 1 mA.

Therefore, the current gain (β) is 333.33x.