Transpose (s) when d=2(s-an)÷n(n-1)?

To transpose the equation when d=2(s-an)÷n(n-1), we need to solve for s.

First, we can multiply both sides by n(n-1) to get rid of the denominator:

n(n-1)d = 2(s-an)

Next, we can distribute the 2 on the right side:

n(n-1)d = 2s - 2an

Now, we can isolate s by moving the terms without s to the other side:

2an = 2s - n(n-1)d

2an = 2s - n^2 + n

Now, we can solve for s by dividing by 2:

s = an + (n^2 - n)/2 + d

Therefore, the transposed equation is s = an + (n^2 - n)/2 + d.

d = 2(s - an) / n(n - 1)
nd = 2(s - an) / (n - 1)
nd(n - 1) = 2(s - an)
nd² - nd = 2s - 2an
nd² - nd - 2s + 2an = 0
(nd² - 2s) + (-nd + 2an) = 0
nd(nd - 2s) - 2(nd - 2an) = 0
(nd - 2)(nd - 2s) = 0
nd - 2 = 0 or nd - 2s = 0
nd = 2 or nd = 2s
n = 2/d or s = 2/n
s = 2/n or n = 2/d