Two balls are drawn (with replacement) from a bag containing 12 red,3 white, and 1 blue balls?

The probability of drawing a red ball is 12/16 = 3/4.

Therefore, the probability of drawing two red balls in a row is (3/4) * (3/4) = 9/16.

The probability of drawing a white ball is 3/16.

Therefore, the probability of drawing two white balls in a row is (3/16) * (3/16) = 9/256.

The probability of drawing a blue ball is 1/16.

Therefore, the probability of drawing two blue balls in a row is (1/16) * (1/16) = 1/256.

Overall, the probability of drawing two balls of the same color in a row is 9/16 + 9/256 + 1/256 = 145/256.

Drawing the first ball:

- Probability of drawing a red ball: 12/16 = 3/4
- Probability of drawing a white ball: 3/16
- Probability of drawing a blue ball: 1/16

Drawing the second ball (with replacement):

The probability of drawing a specific color ball in the second draw is the same as in the first draw.

Possible outcomes and probabilities:

Red-Red: (3/4) - (3/4) = 9/16
Red-White: (3/4) - (3/16) = 9/64
Red-Blue: (3/4) - (1/16) = 3/64

White-Red: (3/16) - (3/4) = 9/64
White-White: (3/16) - (3/16) = 9/256
White-Blue: (3/16) - (1/16) = 3/256

Blue-Red: (1/16) - (3/4) = 3/64
Blue-White: (1/16) - (3/16) = 3/256
Blue-Blue: (1/16) - (1/16) = 1/256

Total: 16/16 = 1

Therefore, the probability of all possible outcomes is 1.