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Use a normal ratio 1:3:6.50kg bag of cement is equal to 37litres.bulk density of sand is 1450kg/m3 and stone is 1600kg/m3.calculate the materials needed to construct 8m by 5m and 6m thick?
Anonymous
more than 1 week ago
Use a normal ratio 1:3:6.50kg bag of cement is equal to 37litres.bulk density of sand is 1450kg/m3 and stone is 1600kg/m3.calculate the materials needed to construct 8m by 5m and 6m thick?
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ChatGPT
more than 1 week ago
To calculate the materials needed to construct a structure that is 8m by 5m and 6m thick using a 1:3:6 ratio, we first need to calculate the volume of the structure.
Volume = Length x Width x Height
Volume = 8m x 5m x 6m
Volume = 240 cubic meters
Next, we need to calculate the amount of cement, sand, and stone needed based on the 1:3:6 ratio.
Cement:
1 part cement = 1/10 total parts
1/10 x 240 cubic meters = 24 cubic meters
Sand:
3 parts sand = 3/10 total parts
3/10 x 240 cubic meters = 72 cubic meters
Stone:
6 parts stone = 6/10 total parts
6/10 x 240 cubic meters = 144 cubic meters
Now, we need to convert the volume of each material into weight using their respective bulk densities.
Weight of Cement:
24 cubic meters x 1450 kg/m3 = 34800 kg
Weight of Sand:
72 cubic meters x 1450 kg/m3 = 104400 kg
Weight of Stone:
144 cubic meters x 1600 kg/m3 = 230400 kg
Therefore, to construct a structure that is 8m by 5m and 6m thick using a 1:3:6 ratio, you will need 34,800 kg of cement, 104,400 kg of sand, and 230,400 kg of stone.
Volume = Length x Width x Height
Volume = 8m x 5m x 6m
Volume = 240 cubic meters
Next, we need to calculate the amount of cement, sand, and stone needed based on the 1:3:6 ratio.
Cement:
1 part cement = 1/10 total parts
1/10 x 240 cubic meters = 24 cubic meters
Sand:
3 parts sand = 3/10 total parts
3/10 x 240 cubic meters = 72 cubic meters
Stone:
6 parts stone = 6/10 total parts
6/10 x 240 cubic meters = 144 cubic meters
Now, we need to convert the volume of each material into weight using their respective bulk densities.
Weight of Cement:
24 cubic meters x 1450 kg/m3 = 34800 kg
Weight of Sand:
72 cubic meters x 1450 kg/m3 = 104400 kg
Weight of Stone:
144 cubic meters x 1600 kg/m3 = 230400 kg
Therefore, to construct a structure that is 8m by 5m and 6m thick using a 1:3:6 ratio, you will need 34,800 kg of cement, 104,400 kg of sand, and 230,400 kg of stone.
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Google Gemini AI
more than 1 week ago
Materials Calculations:
Step 1: Calculate the volume of concrete needed
Volume = Length x Width x Height
Volume = 8m x 5m x 6m
Volume = 240m³
Step 2: Determine the quantity of cement needed
Using the normal ratio 1:3:6.50, we can determine the quantity of cement needed per cubic meter of concrete:
Cement: 1 part = x kg
Sand: 3 parts = 3x kg
Stone: 6.50 parts = 6.50x kg
Total weight: 1x + 3x + 6.50x = 10.50x kg
Since 1 bag of cement is equal to 50kg, we can find the number of bags needed:
Bags of cement = Total weight / Bag weight
Bags of cement = 10.50x / 50 kg
Bags of cement = 0.21x
Step 3: Determine the quantity of sand and stone needed
Using the ratio and the number of bags of cement calculated in Step 2, we can find the quantities of sand and stone needed:
Sand: 3x = 3 x 0.21x = 0.63x kg
Stone: 6.50x = 6.50 x 0.21x = 1.365x kg
Step 4: Convert weight to volume
To calculate the volume of sand and stone, we need to use their bulk densities:
Volume of sand = Weight of sand / Bulk density of sand
Volume of sand = 0.63x kg / 1450 kg/m³
Volume of sand = 0.000434x m³
Volume of stone = Weight of stone / Bulk density of stone
Volume of stone = 1.365x kg / 1600 kg/m³
Volume of stone = 0.000853x m³
Step 5: Calculate the total materials needed for 240m³ of concrete
Total cement: 0.21x x 240 = 50.4x kg (or 1,008 bags)
Total sand: 0.000434x x 240 = 0.104x m³
Total stone: 0.000853x x 240 = 0.205x m³
Therefore, to construct 8m by 5m and 6m thick concrete, you will need:
- Cement: 50.4x kg (or approximately 1,008 bags)
- Sand: 0.104x m³
- Stone: 0.205x m³
Step 1: Calculate the volume of concrete needed
Volume = Length x Width x Height
Volume = 8m x 5m x 6m
Volume = 240m³
Step 2: Determine the quantity of cement needed
Using the normal ratio 1:3:6.50, we can determine the quantity of cement needed per cubic meter of concrete:
Cement: 1 part = x kg
Sand: 3 parts = 3x kg
Stone: 6.50 parts = 6.50x kg
Total weight: 1x + 3x + 6.50x = 10.50x kg
Since 1 bag of cement is equal to 50kg, we can find the number of bags needed:
Bags of cement = Total weight / Bag weight
Bags of cement = 10.50x / 50 kg
Bags of cement = 0.21x
Step 3: Determine the quantity of sand and stone needed
Using the ratio and the number of bags of cement calculated in Step 2, we can find the quantities of sand and stone needed:
Sand: 3x = 3 x 0.21x = 0.63x kg
Stone: 6.50x = 6.50 x 0.21x = 1.365x kg
Step 4: Convert weight to volume
To calculate the volume of sand and stone, we need to use their bulk densities:
Volume of sand = Weight of sand / Bulk density of sand
Volume of sand = 0.63x kg / 1450 kg/m³
Volume of sand = 0.000434x m³
Volume of stone = Weight of stone / Bulk density of stone
Volume of stone = 1.365x kg / 1600 kg/m³
Volume of stone = 0.000853x m³
Step 5: Calculate the total materials needed for 240m³ of concrete
Total cement: 0.21x x 240 = 50.4x kg (or 1,008 bags)
Total sand: 0.000434x x 240 = 0.104x m³
Total stone: 0.000853x x 240 = 0.205x m³
Therefore, to construct 8m by 5m and 6m thick concrete, you will need:
- Cement: 50.4x kg (or approximately 1,008 bags)
- Sand: 0.104x m³
- Stone: 0.205x m³
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