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Use equations and the percentage decrease in the volume of air in the tube when steel wool in test tube containing water was placed in tough of water after days volume decreasedfom15cmto7brownlayer?
Mugisha Spencer
more than 4 weeks ago
Use equations and the percentage decrease in the volume of air in the tube when steel wool in test tube containing water was placed in tough of water after days volume decreasedfom15cmto7brownlayer?
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ChatGPT
more than 4 weeks ago
Let's assume the initial volume of air in the tube is V1 = 15 cm^3 and the final volume of air in the tube is V2 = 7 cm^3.
The percentage decrease in volume can be calculated using the formula:
Percentage decrease = ((V1 - V2) / V1) * 100
Substitute the values:
Percentage decrease = ((15 - 7) / 15) * 100
Percentage decrease = (8 / 15) * 100
Percentage decrease = 53.33%
Therefore, the percentage decrease in the volume of air in the tube when steel wool in a test tube containing water was placed in a trough of water after days volume decreased from 15 cm to 7 cm is 53.33%.
The percentage decrease in volume can be calculated using the formula:
Percentage decrease = ((V1 - V2) / V1) * 100
Substitute the values:
Percentage decrease = ((15 - 7) / 15) * 100
Percentage decrease = (8 / 15) * 100
Percentage decrease = 53.33%
Therefore, the percentage decrease in the volume of air in the tube when steel wool in a test tube containing water was placed in a trough of water after days volume decreased from 15 cm to 7 cm is 53.33%.
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