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What is the pressure (in kPa) of 0.4 mol of hydrogen in a container of volume 8L at 27 degree Celsius?
John Gunurei
Feb 25
What is the pressure (in kPa) of 0.4 mol of hydrogen in a container of volume 8L at 27 degree Celsius?
Exact solution working to this question please?
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ChatGPT
Feb 25
To calculate the pressure of the hydrogen gas, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (in kPa)
V = volume (in L)
n = number of moles
R = ideal gas constant (8.31 J/mol*K)
T = temperature (in Kelvin)
First, we need to convert the temperature from Celsius to Kelvin:
27°C + 273 = 300 K
Now we can plug in the values into the equation:
P(8) = (0.4)(8.31)(300)
P(8) = 99.6
P = 99.6 / 8
P = 12.45 kPa
Therefore, the pressure of 0.4 mol of hydrogen in a container of volume 8L at 27 degrees Celsius is 12.45 kPa.
PV = nRT
Where:
P = pressure (in kPa)
V = volume (in L)
n = number of moles
R = ideal gas constant (8.31 J/mol*K)
T = temperature (in Kelvin)
First, we need to convert the temperature from Celsius to Kelvin:
27°C + 273 = 300 K
Now we can plug in the values into the equation:
P(8) = (0.4)(8.31)(300)
P(8) = 99.6
P = 99.6 / 8
P = 12.45 kPa
Therefore, the pressure of 0.4 mol of hydrogen in a container of volume 8L at 27 degrees Celsius is 12.45 kPa.
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