What is the velocity of the body when it is just about strike the ground where Mass of the body is 5kgs is raised to a height of 1.8metres?

To find the velocity of the body just before it strikes the ground, we can use the principle of conservation of energy.

The potential energy of the body at the initial height is given by:
PE = mgh
PE = 5kg * 9.8m/s^2 * 1.8m
PE = 88.2 Joules

At the ground level, all the potential energy is converted into kinetic energy. Therefore, the kinetic energy of the body just before striking the ground is equal to the potential energy at the initial height:
KE = PE
1/2 * m * v^2 = 88.2
1/2 * 5kg * v^2 = 88.2
2.5 * v^2 = 88.2
v^2 = 88.2 / 2.5
v^2 = 35.28
v = sqrt(35.28)
v ≈ 5.94 m/s

Therefore, the velocity of the body just before striking the ground is approximately 5.94 m/s.

The body of mass 30 km hangs 50m above the ground calculate a potential energy