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#mathematics
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#physics
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When a 0.45g air rifle pallet is fired in target attache to glider on linear air track, the glider moves 50cm in 3.8s.Caluclate velocity of pellet.The glider and target have combine mass of 643g?

more than 3 weeks ago

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more than 3 weeks ago

First, we need to calculate the momentum of the pellet before it hits the glider.

Given:

Mass of pellet (m1) = 0.45g = 0.00045kg

Initial velocity of pellet (u1) = 0 m/s (as it is fired from rest)

Momentum of pellet before hitting the glider:

p1 = m1 * u1 = 0.00045kg * 0 = 0 kg m/s

Now, we need to calculate the velocity of the glider after the pellet hits it.

Given:

Combined mass of glider and target (m2) = 643g = 0.643kg

Distance moved by glider (s) = 50cm = 0.5m

Time taken for glider to move (t) = 3.8s

Using the equation of motion:

s = (u2 + u1) * t / 2

0.5 = (u2 + 0) * 3.8 / 2

u2 = 0.5 * 2 / 3.8

u2 = 0.2632 m/s

Now, we can calculate the velocity of the pellet after hitting the glider using the principle of conservation of momentum:

Initial momentum = Final momentum

m1 * u1 = (m1 + m2) * u2

0 = (0.00045 + 0.643) * u2

u2 = 0 / 0.64345

u2 = 0 m/s

Therefore, the velocity of the pellet after hitting the glider is 0 m/s.

Given:

Mass of pellet (m1) = 0.45g = 0.00045kg

Initial velocity of pellet (u1) = 0 m/s (as it is fired from rest)

Momentum of pellet before hitting the glider:

p1 = m1 * u1 = 0.00045kg * 0 = 0 kg m/s

Now, we need to calculate the velocity of the glider after the pellet hits it.

Given:

Combined mass of glider and target (m2) = 643g = 0.643kg

Distance moved by glider (s) = 50cm = 0.5m

Time taken for glider to move (t) = 3.8s

Using the equation of motion:

s = (u2 + u1) * t / 2

0.5 = (u2 + 0) * 3.8 / 2

u2 = 0.5 * 2 / 3.8

u2 = 0.2632 m/s

Now, we can calculate the velocity of the pellet after hitting the glider using the principle of conservation of momentum:

Initial momentum = Final momentum

m1 * u1 = (m1 + m2) * u2

0 = (0.00045 + 0.643) * u2

u2 = 0 / 0.64345

u2 = 0 m/s

Therefore, the velocity of the pellet after hitting the glider is 0 m/s.

Google Gemini AI

more than 3 weeks ago

Momentum of pellet and glider was conserved.

Momentum=mass x velocity

Momentum of pellet before firing=0 as it is at rest

Momentum of pellet after firing=0.45g(V)

Momentum of glider and target before firing=0(at rest)

Momentum of glider and target after firing=(643+0.45)g(u)

=643.45gu

Momentum of pellet=momentum of glider and target

0.45gV=643.45gu

V=(643.45gu)/0.45g

Velocity of pellet(V)=1430u

Therefore since u=50cm/3.8s

V=1430(50/3.8)

**V=18842.1cm/s**

Momentum=mass x velocity

Momentum of pellet before firing=0 as it is at rest

Momentum of pellet after firing=0.45g(V)

Momentum of glider and target before firing=0(at rest)

Momentum of glider and target after firing=(643+0.45)g(u)

=643.45gu

Momentum of pellet=momentum of glider and target

0.45gV=643.45gu

V=(643.45gu)/0.45g

Velocity of pellet(V)=1430u

Therefore since u=50cm/3.8s

V=1430(50/3.8)