Calculate the mass of hydrogen chloride (HCl) produced by the reaction b/n 8g of hydrogen and an excess of chlorine??

To calculate the mass of hydrogen chloride (HCl) produced, we need to determine the limiting reactant first. The limiting reactant is the reactant that is completely consumed in the reaction and determines the maximum amount of product that can be formed.

The balanced chemical equation for the reaction between hydrogen (H2) and chlorine (Cl2) to form hydrogen chloride (HCl) is:

H2 + Cl2 -> 2HCl

From the equation, we can see that 1 mole of hydrogen (H2) reacts with 1 mole of chlorine (Cl2) to produce 2 moles of hydrogen chloride (HCl).

To find the limiting reactant, we need to compare the number of moles of each reactant. We can use the molar mass of each element to convert the given mass of hydrogen (H2) into moles.

The molar mass of hydrogen (H2) is 2 g/mol. Therefore, 8 g of hydrogen (H2) is equal to 8 g / 2 g/mol = 4 mol.

Since there is an excess of chlorine (Cl2), we can assume that all 4 moles of hydrogen (H2) react completely.

From the balanced equation, we know that 1 mole of hydrogen (H2) reacts to produce 2 moles of hydrogen chloride (HCl). Therefore, 4 moles of hydrogen (H2) will produce 4 moles x 2 moles/mol = 8 moles of hydrogen chloride (HCl).

Finally, we can calculate the mass of hydrogen chloride (HCl) produced by multiplying the number of moles by the molar mass of hydrogen chloride (HCl).

The molar mass of hydrogen chloride (HCl) is 36.5 g/mol.

Mass of hydrogen chloride (HCl) = 8 moles x 36.5 g/mol = 292 g

Therefore, the mass of hydrogen chloride (HCl) produced by the reaction between 8 g of hydrogen and an excess of chlorine is 292 g.

The first order reaction is 90% complete in 428 minutes.
(a) Calculate the first and second half-lives for this reaction.
(b)How long does it take for 80% of the reaction to be complete?