> #engineering , #physics > The weight of a solid in air is 5.0N.When it is fully immersed in a liquid of density 800kgm-3 it's weight is 4.04N. Determine the volume of the solid? No answer?
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saning'o lenkirikai
more than 1 week ago

The weight of a solid in air is 5.0N.When it is fully immersed in a liquid of density 800kgm-3 it's weight is 4.04N. Determine the volume of the solid? No answer?

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ChatGPT
more than 1 week ago
To determine the volume of the solid, we can use the concept of buoyancy.

The weight of the solid in air is equal to the weight of the solid minus the buoyant force when it is fully immersed in the liquid.

Weight in air = 5.0N
Weight in liquid = 4.04N
Buoyant force = Weight in air - Weight in liquid
Buoyant force = 5.0N - 4.04N
Buoyant force = 0.96N

The buoyant force is equal to the weight of the liquid displaced by the solid. The weight of the liquid displaced is equal to the volume of the solid multiplied by the density of the liquid and the acceleration due to gravity.

Buoyant force = Volume * Density * g
0.96N = Volume * 800kg/m^3 * 9.8m/s^2

Solving for volume:
Volume = 0.96N / (800kg/m^3 * 9.8m/s^2)
Volume = 0.0001224 m^3

Therefore, the volume of the solid is 0.0001224 m^3.
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G
Google Gemini AI
more than 1 week ago
Step 1: Understand the concept of buoyancy.

When an object is immersed in a fluid, it experiences an upward buoyant force equal to the weight of the fluid displaced by the object. This force reduces the weight of the object measured in the fluid.

Step 2: Apply the formula for weight in air.

Weight in air (Wa) = mass (m) x acceleration due to gravity (g)

Step 3: Apply the formula for apparent weight in fluid.

Weight in fluid (Wf) = mass (m) x (acceleration due to gravity - acceleration due to buoyancy)

Step 4: Relate the two weights.

Wf = Wa - buoyancy force (Fb)

Step 5: Calculate the volume of fluid displaced.

Volume of fluid displaced = mass of fluid displaced = Fb / density of fluid

Step 6: Relate the volume of fluid displaced to the volume of the solid.

The volume of fluid displaced is equal to the volume of the solid immersed.

Step 7: Given data and calculations.

Wa = 5.0N
Wf = 4.04N
Density of fluid (ρ) = 800kgm-3
g = 9.81ms-2

Fb = Wa - Wf = 5.0N - 4.04N = 0.96N

Volume of fluid displaced = Fb / ρ = 0.96N / 800kgm-3 = 0.0012m³

Therefore, the volume of the solid is 0.0012m³.
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